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junior college 1 | H2 Maths
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Hi! Can someone pls help me with this? I can’t get the answer, thank u so much!
= (4 - x)-¹⁄²
= (4(1 - ¼x))-¹⁄²
= 4-¹⁄² (1 - ¼x)-¹/²
= ½ (1 + (-½)(-¼x) + (-½)(-½ - 1)/2! (-¼x)² +...)
= ½(1 + ⅛x + (-½)(-3/2)/2 (1/16 x²) + ...)
= ½ + 1/16 x + 1/256 x² + ...
(Maclaurin expansion)
So (1 + ax-¹) / √(4 - x)
= (1 + a/x) (½ + 1/16 x + 1/256 x² + ...)
Term independent of x
= 1(½) + (a/x) (1/16 x)
½ + a/16
½ + a/16 = 5
a/16 = 4½ = 9/2
a = 16 x 9/2 = 72
Actually it's...
½ + 1/16 x + 3/256 x² + ...
But no idea what that 1b) is (since she didn't show that part) so just did one extra term. The 1b) may have asked for up to a specific term
See 1 Answer
Usually they tend to ask three or four, and here they actually didn’t specify (even though we know only the first two terms are needed), so for the benefit of the doubt, I gave four terms.
Sonia, it would be better if you provided the first part so as to set the context for the second part (that you are asking for)
One of my students who have completed the full syllabus of A Maths two months ago actually forgot how to do logarithms learnt in Sec 3.