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secondary 3 | A Maths
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need help with this qn,, pls explain too (my cher alr go through corrections but i understand nothing)
Date Posted: 4 years ago
Views: 195
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So u need to understand the rules of logarithm.
lg A + lg B = lg (AxB)
lg A - lg B = lg (A/B)
N lg A = lg (A^n)
Same applies for “ln”
Therefore, ur answer shld be:
1+ln8-2ln2
= 1+ln8-ln2^2
= 1+ln(8/4)
= 1+ln2
lg A + lg B = lg (AxB)
lg A - lg B = lg (A/B)
N lg A = lg (A^n)
Same applies for “ln”
Therefore, ur answer shld be:
1+ln8-2ln2
= 1+ln8-ln2^2
= 1+ln(8/4)
= 1+ln2
Sorry incomplete. Okay so you also need to know that:
ln e or lg 10 = 1 so the answer should continue with lne+ln2=ln2e
ln e or lg 10 = 1 so the answer should continue with lne+ln2=ln2e
1 + ln 8 - 2 ln 2
= loge e + ln 8 - ln 2^2
= ln e + ln 8 - ln 4
= ln (8e / 4)
= ln 2e
LockB, you can start writing with loge if you are not comfortable with writing ln immediately.
= loge e + ln 8 - ln 2^2
= ln e + ln 8 - ln 4
= ln (8e / 4)
= ln 2e
LockB, you can start writing with loge if you are not comfortable with writing ln immediately.
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