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secondary 3 | A Maths
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Hi, I need help with this question. Thanks
Date Posted: 3 years ago
Views: 452
log3 a = x ①
log81 b = y ②
a/b = 3^c ③
From ①, a = 3^x
From ②, b = 81^y = (3⁴)^y = 3^(4y)
So,
a/b
= 3^x / 3^(4y)
= 3^(x - 4y)
Since a/b = 3^c , (from ③)
Then 3^c = 3^(x - 4y)
Comparing exponents,
c = x - 4y
log81 b = y ②
a/b = 3^c ③
From ①, a = 3^x
From ②, b = 81^y = (3⁴)^y = 3^(4y)
So,
a/b
= 3^x / 3^(4y)
= 3^(x - 4y)
Since a/b = 3^c , (from ③)
Then 3^c = 3^(x - 4y)
Comparing exponents,
c = x - 4y
Thank you so much :)
Welcome
See 2 Answers
done
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Hello, there you go...
Date Posted:
3 years ago
Thank you so much :)
Thank you so much :)
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