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secondary 4 | A Maths
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This is a kinematic question but I’m unsure of how to use kinematic equation to solve it....I nd help!
Date Posted: 3 years ago
Views: 223
Let the time taken to reach the top speed be t s.
Acceleration of person
= 10.6/t m/s2
Total distance moved during this period
= 1/2 * t * 10.6
= 5.3t m
Assume that the person reaches top speed before completing the 100 m distance.
Let the time taken to complete the remaining race be (10.5 - t) seconds.
Distance covered in this period
= 10.6 * (10.5 - t)
= 111.3 - 10.6t m
Total distance covered
= 5.3t + 111.3 - 10.6t
= 111.3 - 5.3t
Since he travels 100 m,
111.3 - 5.3t = 100
11.3 = 5.3t
t = 2.132075472
So he takes 2.13 s to accelerate to top speed.
Acceleration
= 10.6 / 2.132...
= 4.971681416...
~ 4.97 m/s2
Acceleration of person
= 10.6/t m/s2
Total distance moved during this period
= 1/2 * t * 10.6
= 5.3t m
Assume that the person reaches top speed before completing the 100 m distance.
Let the time taken to complete the remaining race be (10.5 - t) seconds.
Distance covered in this period
= 10.6 * (10.5 - t)
= 111.3 - 10.6t m
Total distance covered
= 5.3t + 111.3 - 10.6t
= 111.3 - 5.3t
Since he travels 100 m,
111.3 - 5.3t = 100
11.3 = 5.3t
t = 2.132075472
So he takes 2.13 s to accelerate to top speed.
Acceleration
= 10.6 / 2.132...
= 4.971681416...
~ 4.97 m/s2
See 1 Answer
done
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Hello Nelson, there you go.
Date Posted:
3 years ago
I have used only the kinematics equations.
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