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Is this really a primary 6 question? Can use algebra to solve it?
Date Posted:
3 years ago
Question was not very clear. It never specify not pupils select 1 type of food only.
@ AC Lim's, Agree, I had to read the question repeatedly to get it right.
To Xeno, sorry if I did not explain it clearly in my workings. The 4 who liked all types of food are counted in all groups, E.g
For 60% who liked Jap and Korean, it includes the 4 who liked everything. So to get only the percentage of pupils who liked only Jap and Korean, we would have to take:
60% - 2x, where 2x is 4 expressed in percentage terms.
Likewise for the other two groups. We then add all three groups together, add in the 4 ppl (2x) and the 2 ppl (X) to make up 100% of the students.
To Xeno, sorry if I did not explain it clearly in my workings. The 4 who liked all types of food are counted in all groups, E.g
For 60% who liked Jap and Korean, it includes the 4 who liked everything. So to get only the percentage of pupils who liked only Jap and Korean, we would have to take:
60% - 2x, where 2x is 4 expressed in percentage terms.
Likewise for the other two groups. We then add all three groups together, add in the 4 ppl (2x) and the 2 ppl (X) to make up 100% of the students.
Me too. .. ... Think for about a day on this question.
From your working, it can straight away use 4 and 2 instead of 2x and x.
60%-4 + 30%-4 + 25%-4 +4 +2=100%
115%-4-4+2=100%
15% →6
100% = 100% ÷ 15% × 6 = 40.
But you really produced a good method/working here.
From your working, it can straight away use 4 and 2 instead of 2x and x.
60%-4 + 30%-4 + 25%-4 +4 +2=100%
115%-4-4+2=100%
15% →6
100% = 100% ÷ 15% × 6 = 40.
But you really produced a good method/working here.