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secondary 3 | E Maths
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sally
Sally

secondary 3 chevron_right E Maths chevron_right Singapore

need help for question 9&10

Date Posted: 4 years ago
Views: 251

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Ivan Tan
Ivan Tan's answer
15 answers (Tutor Details)
1st
I'm still trying out question 9, but here's the answer to question 10 first. Hope it helps.
For question 9,
Similar to question 10, use the formula
(sin A / a) = (sin B / b)
sin ABD / AD = sin ADB / AB
sin 25° / 4 = sin ADB / 8
sin ADB = 8 × sin 25° / 4
ADB = sin^-1(8 × sin 25° / 4)

Now you can find the angle of ACD, ACB and BAC.

You can use the same method to find question b and c. Or you can use cosine rule:
a² = b² + c² - 2bc cosA
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Ivan Tan
Ivan Tan's answer
15 answers (Tutor Details)
sally
Sally
3 years ago
urmm but the answer i got from calculator is 57.6972... while the answer on my qn paper is 57°
Ivan Tan
Ivan Tan
3 years ago
Hi Sally,

Maybe check with your teacher if the answer is wrong? Or maybe the answer is rounded off. Because if let's say 57° is correct, we can use sine rule to show:
sinADB / AB = sinABD / AD
sin57° / 8 = sin25° / 4
0.104833821 = 0.1056545654
Since both sides are not equal, 57° is inaccurate.