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Navaneet
Navaneet

Malaysia

Please help me with this, tq

Date Posted: 3 years ago
Views: 333
J
J
3 years ago
fg(x) = (x + 10)/(x + 4)

= (x + 4 + 6)/(x + 4)

= 1 + 6/(x + 4)

= 2(3/(x + 4)) + 1


Comparing with f(x) = px + 1 , g(x) = 3/(x + q),

p = 2, q = 4
J
J
3 years ago
Alternatively,


fg(x)

= p(3/(x + q)) + 1

= 3p/(x + q) + 1

= (3p + x + q)/(x + q)

= (x + 3p + q)/(x + q)

Comparing coefficients,

q = 4 (denominator)

3p + q = 10 (numerator)

3p = 10 - q

3p = 10 - 4 = 6

p = 6 ÷ 3 = 2
Navaneet
Navaneet
3 years ago
Thank U sir.. The answer is correct.. And i understand the workings.. Tqsm..
J
J
3 years ago
Welcome

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Navaneet
Navaneet
3 years ago
Yes just check the answer and its correct, tq very much..