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secondary 4 | E Maths
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Yos
Yos

secondary 4 chevron_right E Maths chevron_right Singapore

I need someone to explain this to me step by step. I don't really understand what my math teacher taught.

Date Posted: 3 years ago
Views: 342
J
J
3 years ago
8x²(x² + 2)² - 2x(4x³ + 1)(x² + 2)

Notice the common factor (x² + 2) for both terms. So we factor that out first.

= 8x²(x² + 2)(x² + 2) - 2x(4x³ + 1)(x² + 2)

= (x² + 2) (8x²(x² + 2) - 2x(4x³ + 1))

Then, expand the terms inside, and simplify

= (x² + 2) (8x⁴ + 16x² - 8x⁴ - 2x)

= (x² + 2) (16x² - 2x)

Now, factorise 16x² - 2x. The common term is 2x so factor that out.

= (x² + 2) ( (8x)(2x) - (1)(2x) )

= (x² + 2)(2x)(8x - 1)

= 2x(8x - 1)(x² + 2)

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joylene allyssa chen
Joylene Allyssa Chen's answer
444 answers (Tutor Details)
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J
J
3 years ago
The question asks to factorise the expression so common terms should be taken out first. What you've done is to simplify and expand the expression instead.
Koflot
Koflot
3 years ago
Is there a way to report her?
She has been purposefully giving the wrong answers (and yes i mean deliberately)
I once caught her even trying to lie to a primary school student.
J
J
3 years ago
You may want to email the administrators of Manytutors if that's the case
J
J
3 years ago
Under the feedback/contact us tab