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Secondary 1 | Maths
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hi can someone help me w these 2
Date Posted: 4 years ago
Views: 237
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First question:
Inversely proportional: when number of students go down, the price must go up.
When 85 students go, price per student is $12
Therefore, when 80 students go, price per student = 85/80 X $12 = $12.75
Inversely proportional: when number of students go down, the price must go up.
When 85 students go, price per student is $12
Therefore, when 80 students go, price per student = 85/80 X $12 = $12.75
Second question:
a)
When t = 5, l = 620
m X t^2 = l
25m = 620
m = 620/25 = 24 4/5
24 4/5 t^2 = l
B)
When t = 3,
l = 24 4/5 * 3^2. = 223.2cm
When l = 155
t = sqroot (155/24.8) = sqroot(6.25) = 2.5cm
a)
When t = 5, l = 620
m X t^2 = l
25m = 620
m = 620/25 = 24 4/5
24 4/5 t^2 = l
B)
When t = 3,
l = 24 4/5 * 3^2. = 223.2cm
When l = 155
t = sqroot (155/24.8) = sqroot(6.25) = 2.5cm
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