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secondary 4 | A Maths
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Help daffodilx! Anyone can contribute an answer, even non-tutors.
I need help with part ii.
Pls help thanks !!!
Date Posted: 7 years ago
Views: 592
The 'Hence' in the question implies that the use of the answer in (i) (in this case, the equation of the perpendicular bisector of PQ).
Now, recall that since 2y=3x+7 is the perpendicular bisector of PQ, any point on the line 2y=3x+7 would be a valid solution for point R.
With this, consider the new information given in (ii); where the question states the R MUST lie on the line y=21-2x.
If you combine the two major ideas from above, you would observe that R must simutaneously satisfy both the equations 2y=3x+7 and y=21-2x. Thus solve using the two simultaneous equations to obtain R.
Now, recall that since 2y=3x+7 is the perpendicular bisector of PQ, any point on the line 2y=3x+7 would be a valid solution for point R.
With this, consider the new information given in (ii); where the question states the R MUST lie on the line y=21-2x.
If you combine the two major ideas from above, you would observe that R must simutaneously satisfy both the equations 2y=3x+7 and y=21-2x. Thus solve using the two simultaneous equations to obtain R.
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