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Question
secondary 4 | A Maths
2 Answers Below
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Can anyone help me with this? It looks so simple yet I can’t do it
Date Posted: 4 years ago
Views: 351
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done
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There you go
Date Posted:
4 years ago
That was fast HAHAHA
Thank you so much!
Thank you so much!
By the way, log(x)=0 when x=1.
Sorry I misread the question. I should express y in terms of x. But the way to solve it is the same.
It’s okay! Thank you still
done
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You can do it this way too.
Date Posted:
4 years ago
Woah thank you for the effort
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