For part a. you need to convert y √x = ax - bx² into a linear form Y = mX + c.

I see that y √x satisfies the condition for Y and ax satisfies the condition for mX. However, the last expresion, - bx², does not satisfy the condition for c. As such, the equation is not in a linear form, so we need to transform the equation.

We need to get rid of either the x or the x^2 on the right side so that one of the terms is free of the variables x or y.

DIviding throughout by x,
y/√x = a - bx
y/√x = -bx + a

Is this now linear? Take a look.

y/√x satisfies the condition for Y.
-bx satisfies the condition for mX.
a satisfies the condition for c.

And there you are. The linear form to plot.

y/√x = -bx + a, where
Y = y/√x
X = x
m (gradient of line) = -b
c (vertical intercept) = a

You need to obtain values of y/√x from the given data points of y and x, and then plot the coordinates (x, y/√x) on the axes, using y/√x as the vertical axis and x as the horizontal axis.

Then, we plot the points (x, y/√x) on the graph paper and draw a best fit line.