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secondary 3 | A Maths
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Coordinate geometry
Date Posted: 4 years ago
Views: 265
use gradient = (y1-y2) / (x1-x2)
and product of gradients of 2 perpendicular lines is -1
so,
gradient of AB x gradient of BC = -1
[(1-4) / (1-(-1))] x [(k-4)/(6-(-1))] = -1
(-3/2) x (k-4)/7 = -1
gives k = 26/3
and product of gradients of 2 perpendicular lines is -1
so,
gradient of AB x gradient of BC = -1
[(1-4) / (1-(-1))] x [(k-4)/(6-(-1))] = -1
(-3/2) x (k-4)/7 = -1
gives k = 26/3
Thank u
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The product of two perpendicular bisectors is -1
Date Posted:
4 years ago
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