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primary 5 | Maths
| Area & Volume
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Dear AC lim kindly help this one also tks a lot
Date Posted: 4 years ago
Views: 290
Since they have the same height, then 2 heights = 12cm
1 height = 12cm ÷ 2 = 6cm
Each triangle area
= ½ x base x height
= ½ x base x 6cm
= 3cm x base
But notice that their bases all add up to 21cm. And they have the same height
So total area of all the triangles
= 3cm x (base of A) + 3cm x (base of B) + 3cm x (base of C) + 3cm x (base of D) + 3cm x (base of E)
= 3cm x (base A + base B + base C + base D + base E)
= 3cm x (combined base length)
= 3cm x 21cm
= 63cm²
1 height = 12cm ÷ 2 = 6cm
Each triangle area
= ½ x base x height
= ½ x base x 6cm
= 3cm x base
But notice that their bases all add up to 21cm. And they have the same height
So total area of all the triangles
= 3cm x (base of A) + 3cm x (base of B) + 3cm x (base of C) + 3cm x (base of D) + 3cm x (base of E)
= 3cm x (base A + base B + base C + base D + base E)
= 3cm x (combined base length)
= 3cm x 21cm
= 63cm²
Edited
Tks a lot
See 1 Answer
done
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Hope this helps
Date Posted:
4 years ago
Thanks a lot of AC lim ,
Very creative way! Might not work if there are obtuse triangles though.
Yes. Application to same height triangle or height are given.
Please help thanks
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