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Secondary 1 | Maths
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Date Posted: 4 years ago
Views: 348
(i)
The length of the largest shaded square and the length of the largest square in each figure is in the following ratio. Try to spot a pattern.
Fig 1: 1 to 2
Fig 2: 2 to 3
Fig 3: 3 to 4
Fig 4: 4 to 5
...
Fig n: n to (n + 1)
because the length of the largest shaded square is the same as the figure number and the length of the largest square is always 1 more than the length of the largest shaded square.
(ii)
If a large square has a length of 65 units, then the large shaded square has a length of 64 units.
Number of WHITE unit squares
= 65 x 65 - 64 x 64
= 129
(iii)
We can't find two identical numbers which multiply to 920 (30 x 30 is 900 but 31 x 31 = 961) so there are no figure in the pattern which contains 920 GREY unit squares.
The length of the largest shaded square and the length of the largest square in each figure is in the following ratio. Try to spot a pattern.
Fig 1: 1 to 2
Fig 2: 2 to 3
Fig 3: 3 to 4
Fig 4: 4 to 5
...
Fig n: n to (n + 1)
because the length of the largest shaded square is the same as the figure number and the length of the largest square is always 1 more than the length of the largest shaded square.
(ii)
If a large square has a length of 65 units, then the large shaded square has a length of 64 units.
Number of WHITE unit squares
= 65 x 65 - 64 x 64
= 129
(iii)
We can't find two identical numbers which multiply to 920 (30 x 30 is 900 but 31 x 31 = 961) so there are no figure in the pattern which contains 920 GREY unit squares.
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Date Posted:
4 years ago
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