Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 4 | A Maths
2 Answers Below
Anyone can contribute an answer, even non-tutors.
Help me please!
Date Posted: 4 years ago
Views: 208
See 2 Answers
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
An idea.
You need to find
- the gradient of our wanted line (which is found by finding the gradient of the given other line 3x + 5y = 13 and using the fact that the product of gradients of two perpendicular lines is -1), which is 5/3, and
- a point in this line (given by the intersection of two lines), which is (10/11, 3/11), then
- form the equation using y = mx + c.
You need to find
- the gradient of our wanted line (which is found by finding the gradient of the given other line 3x + 5y = 13 and using the fact that the product of gradients of two perpendicular lines is -1), which is 5/3, and
- a point in this line (given by the intersection of two lines), which is (10/11, 3/11), then
- form the equation using y = mx + c.
Date Posted:
4 years ago
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Hello, hope it helps!
Date Posted:
4 years ago
360 Tutoring Program