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secondary 3 | A Maths
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Hi Mr Eric,
Here's the other question that I find it challenging and struggling on it this afternoon :(
Pls help. Thanks.
Date Posted: 4 years ago
Views: 298
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Little messy hope it helps:)
Date Posted:
4 years ago
Thanks for your advice, Mr Muhammad.
Is there any difference between OA and A?
Is there any difference between OA and A?
OA is the length
A is a point. :)
A is a point. :)
Good evening Candice! Was not available in the past one hour plus. I just looked at your post and will do my workings now.
oic, thank you Mr Muhammad.
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Good evening Candice! Here are my workings for this question. There is, however, a slightly more advanced idea which can shorten my workings heavily based on what we call product of roots (from the topic sum and roots of a quadratic equation, which is out of the A Maths syllabus from this year's Sec 3 onwards).
This is because at the x-axis (for points A and B, with roots a and b),
x² - 6x + 8 = 0
Without factorising this, I can tell that the product OA x OB is basically the product of the two roots ab, which I can read off as constant term / coefficient of x² which equals 8.
Similarly, at the y-axis (for points C and D, with roots c and d),
y² - 9y + 8 = 0
Without factorising this, I can tell that the product OC x OD is basically the product of the two roots cd, which I can read off as constant term / coefficient of y² which also equals 8.
If you don't understand my typewritten workings above, it's ok, you can use the one I have written out using purple ink. But if you don't understand my purple workings as well, let me know and I will explain them again.
This is because at the x-axis (for points A and B, with roots a and b),
x² - 6x + 8 = 0
Without factorising this, I can tell that the product OA x OB is basically the product of the two roots ab, which I can read off as constant term / coefficient of x² which equals 8.
Similarly, at the y-axis (for points C and D, with roots c and d),
y² - 9y + 8 = 0
Without factorising this, I can tell that the product OC x OD is basically the product of the two roots cd, which I can read off as constant term / coefficient of y² which also equals 8.
If you don't understand my typewritten workings above, it's ok, you can use the one I have written out using purple ink. But if you don't understand my purple workings as well, let me know and I will explain them again.
Date Posted:
4 years ago
Good morning Mr Eric. Once again, thank you so much for the detailed explanation. Really appreciated :)
Have a good day ahead and pls take care.
Have a good day ahead and pls take care.
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