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secondary 4 | E Maths
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Tarah toh
Tarah Toh

secondary 4 chevron_right E Maths chevron_right Singapore

Pls help as soon as possible

Date Posted: 4 years ago
Views: 314
Tan Yick Loong
Tan Yick Loong
4 years ago
Are you able to solve part "a" first and plot the graph (part b)?
Tarah toh
Tarah Toh
4 years ago
Im able to solve part a) but part b) im having a hard time to draw
Eric Nicholas K
Eric Nicholas K
4 years ago
Good afternoon Tarah! For me what I would to is this. If time permits in an exam paper, I would mark additional points in between using smaller dots, to facilitate the drawing of the graphs. I am very sure six data points are insufficient to draw a good curve.
Eric Nicholas K
Eric Nicholas K
4 years ago
If you need me to do the question, I will answer the whole of the question on the Desmos graphing site itself.
Tarah toh
Tarah Toh
4 years ago
Yes please do thnku:))
Eric Nicholas K
Eric Nicholas K
4 years ago
Ok, I will write the comments on Desmos directly (due to a lack of graph paper)

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
Good afternoon Tarah! Here are my workings for this question, all done up on Desmos.

Part a is just plain subbing in of x = 6 and rounding off to 2 decimal places to follow the other data values.

Part b you will need to come up with your own axes and data plotting. You may wish to add additional points on your own to improve the accuracy of your graph, perhaps at the x = 0.5, 1.5, 2.5, 3.5, 4.5 and 5.5 mark.

Part (c), after some rearranging, is just asking us to find the x-coordinates of intersection between the curve and the x-axis.

Part (d) is for us to draw a tangent to the curve at (4, 0.70). I actually "cheated" by using dy/dx and forming the equation of the tangent myself (which obviously you know how to do as well) to have a rough idea of the gradient of the line to draw. This is to ensure that my gradient is not too far off the actual value, because accuracy marks can be lost here.

Part (e) is for us to locate and read off the coordinates of the minimum point. There is no need to do dy/dx here as the turning point should be quite accurately located if you have drawn the graph well.

Let me know if you need more explanation.