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junior college 2 | H3 Maths
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= lim n→∞ e^ [ln{ (1 + 1/n)(1 + 2/n).....(1 + n/n) }¹/ⁿ]
= lim n→∞ e^ [ 1/n ln{ (1 + 1/n)(1 + 2/n).....(1 + n/n) } ]
= e^(lim n→∞ 1/n { ln(1 + 1/n) + ln(1 + 2/n)+ ln(1 + n/n) })
= e^ ∫ ln(x + 1) dx (upper limit 1, lower 0)
= e^ [(x + 1)ln(x + 1) - x] (upper limit 1, lower 0)
= e^(2ln2 - 1)
= e^(ln2² - 1)
= e^(ln4) 1/e
= 4/e
I obtained a different integral (m + n - 1) / mn times integral (0 to pi/2) of [cos^(m + n - 2) x].
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Ultimately integration
Log both sides