Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 4 | A Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Help to solve part (iii)
Date Posted: 4 years ago
Views: 220
The coefficients 2, -3, -k and 6 are reversed in order.
"Let x = 1/u".
"Let x = 1/u".
2 - 3/u - k/u^2 + 6/u^3 = 0
Multiplying throughout by u^3,
2u^3 - 3u^2 - ku + 6 = 0
And use results in part ii to solve it for the value(s) of u, then convert back to 1/x and solve for x.
Multiplying throughout by u^3,
2u^3 - 3u^2 - ku + 6 = 0
And use results in part ii to solve it for the value(s) of u, then convert back to 1/x and solve for x.
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
An idea
Date Posted:
4 years ago
Understood
Thank you
360 Tutoring Program