Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 4 | A Maths
2 Answers Below
Anyone can contribute an answer, even non-tutors.
.
Date Posted: 4 years ago
Views: 289
Attempting
See 2 Answers
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
All normals to circle cut through the centre of circle. Using this we can sub 2 normal eqn together to find coordinates of centre. So left with radius which can find using (5,5). Thereafter just construct the equation.
Date Posted:
4 years ago
Megan, for such questions we need to find the centre of the circle, so we need some lines which pass through the centre of the circle.
These are represented usually by perpendicular bisectors of chords or the normal to the circle (which is technically the line perpendicular to the tangent to the circle at the point of tangency).
The reason for this has something to do with the symmetrical properties of a circle.
With two of such lines (which obviously have to be non-parallel) passing through the centre, their intersection HAS TO BE at the centre (two non-parallel lines intersect at only one point).
Once done, the centre of the circle is defined. The one other thing we need to define for a circle is its radius, which is found by connecting this centre to the point (5, 5) on the circle and calculating its length.
These are represented usually by perpendicular bisectors of chords or the normal to the circle (which is technically the line perpendicular to the tangent to the circle at the point of tangency).
The reason for this has something to do with the symmetrical properties of a circle.
With two of such lines (which obviously have to be non-parallel) passing through the centre, their intersection HAS TO BE at the centre (two non-parallel lines intersect at only one point).
Once done, the centre of the circle is defined. The one other thing we need to define for a circle is its radius, which is found by connecting this centre to the point (5, 5) on the circle and calculating its length.
thank you, now i understand:)
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Turns out the equation of the tangent at (5, 5) is not needed, so you can skip that one.
Also, I drew the line 3y = x + 2 wrongly (it should be sloping upwards), but you get the idea.
Let me know if you need more explanation.
Also, I drew the line 3y = x + 2 wrongly (it should be sloping upwards), but you get the idea.
Let me know if you need more explanation.
Date Posted:
4 years ago
thank you for ur clear explanation :)
360 Tutoring Program