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junior college 1 | H2 Maths
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Elle
Elle

junior college 1 chevron_right H2 Maths chevron_right Singapore

hello pls help me with these questions? Thank u!!

Date Posted: 3 years ago
Views: 300

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
1st
Q7

For part two, observe that gradient is 0 when t = 1 and gradient = infinity when t is too positive small.

The thing is, the denominator t * e^t is already a small fixed number of e when t = 1, and it gets even smaller when t is lowered to decimals, whereas the numerator "increases in magnitude" from 0 to 1 as t goes from 1 to 9 (the negative sign is for downsloping purposes only).

With the magnitude of the numerator increasing to 1 and the denominator decreasing to 0, it is why the tangent becomes steeper and steeper as t goes to zero.
Elle
Elle
3 years ago
Thank u!!
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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
An idea for Q8, which is quite messy. Let me know if you do not understand what I wrote, need more explanation, my workings are too messy etc.
Elle
Elle
3 years ago
may i know how u managed to get the graph for 8 ( iii) ?
Eric Nicholas K
Eric Nicholas K
3 years ago
I plotted this on Desmos parametric calculator using the coordinates (-2a cot t, 2a sin^2 t) and played around with the values of a from 0 to 10.