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secondary 4 | A Maths
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Does anyone know how to do part b? Thank you
= ∫(1,4) 4 dx - ∫(1,4) 3f(x) dx
= [4x] (1,4) + ∫(4,1) 3f(x) dx
= 4(1) - 4(4) + 3∫(4,1) f(x) dx
= 4 - 16 + 3(5)
= 4 - 16 + 15
= 3
∫(1,4) [4 - 3f(x)] dx
= ∫(4,1) (3f(x) - 4) dx
= ∫(4,1) 3f(x) dx - ∫(4,1) 4 dx
= 3 ∫(4,1) f(x) dx - [4x] (4,1)
= 3(5) - [4(4) - 4(1)]
= 15 - 16 + 4
= 3
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