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secondary 2 | Maths
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Hello can someone please help me with part 15ii). The answer for part 15i) is 3(x+9)(x+7)
Date Posted: 4 years ago
Views: 262
Use x = 10 for the first part to convert the expression into 969.
Also use x = 10 for the factorised form. Those are the two factors of 969.
Also use x = 10 for the factorised form. Those are the two factors of 969.
3x2 + 48x + 189
= 3 (x2 + 16x + 63)
= 3 (x + 9) (x + 7)
When x = 10,
LHS = 3x2 + 48x + 189 = 300 + 480 + 189 = 969
RHS = 3 (x + 9) (x + 7) = 3 (19) (17)
So the three prime numbers are 3, 17 and 19.
= 3 (x2 + 16x + 63)
= 3 (x + 9) (x + 7)
When x = 10,
LHS = 3x2 + 48x + 189 = 300 + 480 + 189 = 969
RHS = 3 (x + 9) (x + 7) = 3 (19) (17)
So the three prime numbers are 3, 17 and 19.
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Date Posted:
4 years ago
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