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Part b is asking you to calculate the mean and standard deviation of the distance again but replacing the 5.2 with 0.
Your new mean should be about 3.633 and standard deviation is about 1.806
Your new mean should be about 3.633 and standard deviation is about 1.806
I dont get it... can you show me the method instead?
Your 6 values are now: 4.5, 3.9, 4.7, 4.1, 0, 4.6.
Use the same mean and standard deviation formula as what you did in part a.
Use the same mean and standard deviation formula as what you did in part a.