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Part i, ii and a bit of iii
Date Posted:
4 years ago
Alright !! Thank you so much for your help !! Appreciate it alot :))))
the image of the question is not very clear. however, I think I see the no. of spaniels, retrievers and poodles as 10, 14 and 6 respectively. in that case, for part (i) the calculation should be …
case 1: 10C2 x 14C2 x 6C3 = 81900
case 2: 10C1 x 14C3 x 6C3 = 72800
case 3: 10C1 x 14C2 x 6C4 = 13650
total = 81900 + 72800 + 13650 = 168350
Answer : 168,350 selections
case 1: 10C2 x 14C2 x 6C3 = 81900
case 2: 10C1 x 14C3 x 6C3 = 72800
case 3: 10C1 x 14C2 x 6C4 = 13650
total = 81900 + 72800 + 13650 = 168350
Answer : 168,350 selections
Okay will do, it's better to understand now, thank you ! :))
Part i my bad lol
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The rest of iii, and an alternative solution involving the almighty cheryl
Date Posted:
4 years ago