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secondary 4 | A Maths
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Elena
Elena

secondary 4 chevron_right A Maths chevron_right Singapore

I dun know how to do. Pls provide step by step workings thanks

Date Posted: 4 years ago
Views: 214
Muhammad
Muhammad
4 years ago
Sorry, careless mistake on my end.
The area under the curve should be
((1^3)/3 + 1) - ((0^3)/3 + 0)
= 4/3 - 0
Instead of
4/3 - 1
Area under curve is
4/3 + 3
= 4 1/3

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Muhammad
Muhammad's answer
356 answers (Tutor Details)
1st
Hope this helps:)
Eric Nicholas K
Eric Nicholas K
4 years ago
Actually it’s [1^3 / 3 + 1] - [0^3 / 3 + 0]
Muhammad
Muhammad
4 years ago
Oh yeah. Careless of me
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LIM JI HWEE
Lim Ji Hwee's answer
29 answers (Tutor Details)
Integration techniques needed