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Secondary 1 | Maths
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Nancy
Nancy

Secondary 1 chevron_right Maths chevron_right Singapore

Pls help

Date Posted: 4 years ago
Views: 295
Fiona Tan
Fiona Tan
4 years ago
What is the qns? Solve? Expand? Factorise?
Fiona Tan
Fiona Tan
4 years ago
To solve the qns.
x-4(x-3)=3(5+2x)
You should always solve the brackets first so expand them:
x-4x+12=15+6x
Take note if “-“ x “-“ it should be “+” its the law.
Then u solve them, always make “x” positive cuz it will be easier to solve.
6x+4x-x-12+15=0
X+3=0
Then
X=-3
Cuz u bring over from “+” to “-“
THIS IS THE CORRECT VERSION!!
The photo got mistake.
J
J
4 years ago
Both are incorrect at the 2nd last step. Realise that 6x + 4x - x = 9x, not x

Edit: a better way is to group all x terms on one side and constants on the other side.
Nancy
Nancy
4 years ago
Hii everyone thx for replying to my question quick :)

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AC Lim
Ac Lim's answer
12417 answers (A Helpful Person)
Hope this helps
Nancy
Nancy
4 years ago
Hii thx for the helppp
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Fiona Tan
Fiona Tan's answer
1 answers (A Helpful Person)
1st
If its solve this is the way
Sherry Chen
Sherry Chen
4 years ago
You confused yourself when you tried to shift everything to one side. Your error(s) came in from solving (6x + 4x - 12 + 15 - x = 0) onwards.

But still, train of thought is there.
J
J
4 years ago
Probably just carelessness in that 6x + 4x - x = 9x instead of x
Sherry Chen
Sherry Chen
4 years ago
Yeah.
And X + 3 = 0 doesn’t lead to x = 3

Careless mistake it is!
J
J
4 years ago
x + 3 she addressed in the main comments section already. But not the other one.
Sherry Chen
Sherry Chen
4 years ago
Ah, I must have missed the comment. Thanks for pointing out!
Fiona Tan
Fiona Tan
4 years ago
Thanks guys For correcting me:)