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secondary 4 | E Maths
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R
R

secondary 4 chevron_right E Maths chevron_right Singapore

Hi I really don’t understand qn (b) like why is it 6 times 6?? And not 6 times 2 since there r two dice with six sides each? And it confuses me cuz qn (a) says that a smaller number has to be subtracted from a larger number someone plss explain thoroughly thxxxx

Date Posted: 4 years ago
Views: 191
J
J
4 years ago
6 possible outcomes for first die
(1,2,3,4,5,6)

For each of these outcomes, there are 6 possible outcomes for the second die
(1,2,3,4,5,6)

Total number of possible outcomes
= 6 x 6
= 36
J
J
4 years ago
If you list out the possible outcomes,


1,1
1,2
1,3
1,4
1,5
1,6

2,1
2,2
2,3
2,4
2,5
2,6

3,1
3,2
3,3
3,4
3,5
3,6

4,1
4,2
4,3
4,4
4,5
4,6

5,1
5,2
5,3
5,4
5,5
5,6

6,1
6,2
6,3
6,4
6,5
6,6
J
J
4 years ago
If you look at all the possible outcomes, the only ones that can give you a score of 4 are :

1,5
5,1
2,6
6,2

That's 4 outcomes.

Required Probability

= 4/36
= 1/9
R
R
4 years ago
Hi i understand qn b the other part now but I still don’t really get the other part cuz when I count it’s still 12 outcomes r u able to explain abit further so soryy? Abit confused
J
J
4 years ago
Refer to my first comment again. For each one of the 6 possible outcomes for the first die, there are 6 possible outcomes for the second die.

Also, I've listed out all 36 possible outcomes in the second comment. Note that the first die and the second die are distinct.

For example , rolling 6,2 is considered a distinct outcome from rolling 2,6, even though the score obtained is 4 for both cases.
J
J
4 years ago
You can't simply multiply the number of faces on each die by the number of dice.

2 x 6 = 12 just tells you that there are 12 faces in total.
J
J
4 years ago
Recall that the score obtained is based on the combined result of the 2 dice (subtracting the smaller value of the 2 from the larger value) , not each individual die.

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Muhammad
Muhammad's answer
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Hope this explains it :)