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Question
Primary 4 | Maths
2 Answers Below
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Please help.
Date Posted: 4 years ago
Views: 681
method 1
after
Y: 1u
T: 8u
at first
Y: 1u+36
T: 8u+8
1u + 36 = 8u + 8
1u = 28/7 = 4
at first. each $40
.
method 2
at first
Y: 5u
T: 5u
after
Y: 5u - 36
T: 5u - 8
5u - 8 = 8 . (5u - 36)
5u - 8 = 40u - 288
1u = 280/35 = 8
at first. each $40
.
.
.
after
Y: 1u
T: 8u
at first
Y: 1u+36
T: 8u+8
1u + 36 = 8u + 8
1u = 28/7 = 4
at first. each $40
.
method 2
at first
Y: 5u
T: 5u
after
Y: 5u - 36
T: 5u - 8
5u - 8 = 8 . (5u - 36)
5u - 8 = 40u - 288
1u = 280/35 = 8
at first. each $40
.
.
.
Yes! Thank you for your help!
See 2 Answers
Thank you for your help! And the cute drawing helped in better visualisation
done
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Hope this helps :)
Date Posted:
4 years ago
Thank you so much for your help! I appreciate it!
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