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junior college 1 | H2 Maths
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h2 chem ! help me pls thanks !
Date Posted: 4 years ago
Views: 321
5 K2C2O4 ≡ 5 C2O4 2- ≡ 2 MnO4 - ≡ 2 KMnO4
Number of mol of KMnO4 required
= 2.00 x 10-³ mol ÷ 5 x 2
= 8.00 x 10-⁴ mol
Volume of KMnO4 required
= 8.00 x 10-⁴ mol ÷ 0.0100 mol/dm³
= 8.00 x 10-² dm³
Number of mol of KMnO4 required
= 2.00 x 10-³ mol ÷ 5 x 2
= 8.00 x 10-⁴ mol
Volume of KMnO4 required
= 8.00 x 10-⁴ mol ÷ 0.0100 mol/dm³
= 8.00 x 10-² dm³
or 0.0800 dm³ (3 s.f)
thank you !
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Remember the units can always be manipulated to get what you want especially if too many reagents can be confusing. Also remember this holds true only because K+:MnO4- is 1:1 otherwise will have to take into consideration the ratio.
Date Posted:
4 years ago
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