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Question
primary 5 | Maths
| Fractions
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please help me with this q . unsure of the answer.
thanks
Date Posted: 4 years ago
Views: 559
3/10 of her coin...
20c = 7u
50c = 3u
From the table... we know 20c have __9
From 1 to 100, 7 x 7 = 49, end with digit 9 only
Therefore 7u = 49
1u = 7
SO, 50c have 3u =3 x 7 =21
Total coins she have = 49+21 = 70 coins.
20c = 7u
50c = 3u
From the table... we know 20c have __9
From 1 to 100, 7 x 7 = 49, end with digit 9 only
Therefore 7u = 49
1u = 7
SO, 50c have 3u =3 x 7 =21
Total coins she have = 49+21 = 70 coins.
See 1 Answer
done
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Hope this helps.
Date Posted:
4 years ago
thanks u so much
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