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secondary 3 | A Maths
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help with question 22 part (ii) please
Date Posted: 4 years ago
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Date Posted:
4 years ago
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Part (I) is an application requiring the a^3-b^3 as mentioned in the previous answer.
To add on to part (II), difference in 2 consecutive odd numbers will ALWAYS result in an integer. (e.g. 3-1/5-3/7-5 etc).
Dividing the general equation of the difference in cubes by anything other than 1 or 2 will result in a non-integer value. So to answer the question, dividing the equation by 4 gives a non-integer hence never divisible by 4.
To add on to part (II), difference in 2 consecutive odd numbers will ALWAYS result in an integer. (e.g. 3-1/5-3/7-5 etc).
Dividing the general equation of the difference in cubes by anything other than 1 or 2 will result in a non-integer value. So to answer the question, dividing the equation by 4 gives a non-integer hence never divisible by 4.
Date Posted:
4 years ago
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