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Secondary 1 | Maths
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Sec 1 Integrated Programme Maths
pls help ☺️☺️
Date Posted: 4 years ago
Views: 410
b/8 - [¼ a - (³/² (b + 2 a)]
= ⅛ b - [¼ a - (³/² b + 3 a)]
= ⅛ b - [¼a - ³/² b - 3 a]
= ⅛ b - ¼ a + ³/² b + 3 a
= ⅛ b + ³/² b + 3 a - ¼ a
= ⅛ b + 12/8 b + 2¾ a
= 13/8 b + 2¾ a
= 1⅝ b + 2¾ a
= ⅛ b - [¼ a - (³/² b + 3 a)]
= ⅛ b - [¼a - ³/² b - 3 a]
= ⅛ b - ¼ a + ³/² b + 3 a
= ⅛ b + ³/² b + 3 a - ¼ a
= ⅛ b + 12/8 b + 2¾ a
= 13/8 b + 2¾ a
= 1⅝ b + 2¾ a
Updated
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Date Posted:
4 years ago
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