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Question
primary 6 | Maths
| Data Analysis
3 Answers Below
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Pls help
Date Posted: 4 years ago
Views: 245
Grouping method :
2 Large for $25, 3 Small for $44
Common multiple of 2 and 3 is 6
(2 x 3 = 6 , 3 x 2 = 6)
Make the two types of jugs have the same number.
6 large jugs : $25 x 3 = $75
6 small jugs : $44 x 2 = $88
Difference in their price
= $88 - $75
= $13
Group every 6 large jugs and 6 small jugs as 1 set . So in every set, the difference in price between the 6 large and 6 small jugs is $13
Total difference = $65
$65 ÷ $13 = 5
This means there are 5 sets.
In one set, there are 12 jugs (6 small + 6 large)
Total number
= 12 jugs x 5
= 60 jugs
2 Large for $25, 3 Small for $44
Common multiple of 2 and 3 is 6
(2 x 3 = 6 , 3 x 2 = 6)
Make the two types of jugs have the same number.
6 large jugs : $25 x 3 = $75
6 small jugs : $44 x 2 = $88
Difference in their price
= $88 - $75
= $13
Group every 6 large jugs and 6 small jugs as 1 set . So in every set, the difference in price between the 6 large and 6 small jugs is $13
Total difference = $65
$65 ÷ $13 = 5
This means there are 5 sets.
In one set, there are 12 jugs (6 small + 6 large)
Total number
= 12 jugs x 5
= 60 jugs
See 3 Answers
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Hello! I hope this is understandable. I’m using algebra for this part.
Date Posted:
4 years ago
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Hope this helps :)
Date Posted:
4 years ago
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Hope this helps :)
Date Posted:
4 years ago
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