Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 4 | A Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
I am uncertain on the part ii)
Date Posted: 4 years ago
Views: 261
sec 2x - tan 2x = √3 / (1 + cosec 2x)
(sec 2x - tan2x)(1 + cosec 2x) = √3
Since you have already proved in i) that
(1 + cosec θ) (sec θ - tanθ) = cot θ,
Then,
cot 2x = (sec 2x - tan2x)(1 + cosec 2x) = √3
So cot 2x = √3
1/tan2x = √3
so tan2x = 1/√3 = √3 / 3
Solve for this.
(The 2x is merely a substitution of θ)
(sec 2x - tan2x)(1 + cosec 2x) = √3
Since you have already proved in i) that
(1 + cosec θ) (sec θ - tanθ) = cot θ,
Then,
cot 2x = (sec 2x - tan2x)(1 + cosec 2x) = √3
So cot 2x = √3
1/tan2x = √3
so tan2x = 1/√3 = √3 / 3
Solve for this.
(The 2x is merely a substitution of θ)
See 1 Answer
360 Tutoring Program