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secondary 3 | A Maths
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Nicky
Nicky

secondary 3 chevron_right A Maths chevron_right Singapore

Help please

Date Posted: 4 years ago
Views: 160
J
J
4 years ago
log5(x⁴/25y)

= log5(x⁴) - log5(25y)

= 4log5(x) - (log5(25) + log5(y))

= 4a - ( log5(5²) + b)

= 4a - (2log5(5) + b)

= 4a - 2 - b
J
J
4 years ago
log2(3x + 6y) = 2 + log2(6)

log2(3x + 6y) = 2log2(2) + log2(6)

log2(3x + 6y) = log2(2²) + log2(6)

log2(3x + 6y) = log2(4 x 6) = log2(24)

This becomes 3x + 6y = 24

So x + 2y = 8


log2(x½) = log4(2y) + 5log8(1)

log2(x½) = log2(2y)/log2(4) + 0

log2(x½) = log2(2y)/log2(2²)

log2(x½) = log2(2y)/2

2log2(x½) = log2(2y)

log2(x½)² = log2(2y)

log2(x) = log2(2y)

x = 2y