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How to answer the logic circuit using truth table
repeat for each combination of inputs.
by formula, the equivalent formula is ...
F = (((NOT A) NOR B) OR C) NAND (C XOR (B AND (NOT D)))
A = 0, B = 0, C = 0, D = 0 gives
F = (((NOT 0) NOR 0) OR 0) NAND (0 XOR (0 AND (NOT 0)))
= ((1 NOR 0) OR 0) NAND (0 XOR (0 AND 1))
= (0 OR 0) NAND (0 XOR 0)
= 0 NAND 0
= 1
A = 0, B = 0, C = 0, D = 1 gives
F = (((NOT 0) NOR 0) OR 0) NAND (0 XOR (0 AND (NOT 1)))
= ((1 NOR 0) OR 0) NAND (0 XOR (0 AND 0))
= (0 OR 0) NAND (0 XOR 0)
= 0 NAND 0
= 1
A = 0, B = 0, C = 1, D = 0 gives
F = (((NOT 0) NOR 0) OR 1) NAND (1 XOR (0 AND (NOT 0)))
= ((1 NOR 0) OR 1) NAND (1 XOR (0 AND 1))
= (0 OR 1) NAND (1 XOR 0)
= 1 NAND 1
= 0
... and so on
summary
A B C D -> F
--------------
0 0 0 0 -> 1
0 0 0 1 -> 1
0 0 1 0 -> 0
0 0 1 1 -> 0
0 1 0 0 -> 1
0 1 0 1 -> 1
0 1 1 0 -> 1
0 1 1 1 -> 0
1 0 0 0 -> 1
1 0 0 1 -> 1
1 0 1 0 -> 0
1 0 1 1 -> 0
1 1 0 0 -> 1
1 1 0 1 -> 1
1 1 1 0 -> 1
1 1 1 1 -> 0