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Secondary 1 | Maths
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How to do this question pls help!!
Date Posted: 4 years ago
Views: 216
67.45g
Below that, it will be rounded to 67.4g (nearest 0.1g)
(Example : Even if you have 67.44999999999999....g it will be rounded down)
Below that, it will be rounded to 67.4g (nearest 0.1g)
(Example : Even if you have 67.44999999999999....g it will be rounded down)
To find the greatest possible mass of 1 cm³ of the box, use the greatest possible mass of the whole box and divide it by the smallest possible volume of the box.
Smallest possible volume of the box
= 18.5 cm³ (if it were lower, will be rounded down to 18 cm³ eg. 18.499999999... cm³)
Greatest possible mass of the box
= 67.549999999999..... g
(If it were higher , it would be rounded up to 67.6 g for example, 67.55g ≈ 67.6 g (nearest 0.1g) )
So 67.5499999999...g ÷ 18.5 cm³
= 3.65135135135.... g/cm³
Smallest possible volume of the box
= 18.5 cm³ (if it were lower, will be rounded down to 18 cm³ eg. 18.499999999... cm³)
Greatest possible mass of the box
= 67.549999999999..... g
(If it were higher , it would be rounded up to 67.6 g for example, 67.55g ≈ 67.6 g (nearest 0.1g) )
So 67.5499999999...g ÷ 18.5 cm³
= 3.65135135135.... g/cm³
See 1 Answer
done
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Hope it helps
Date Posted:
4 years ago
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