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Question
Secondary 1 | Maths
2 Answers Below
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I need help ASAP !!
Date Posted: 4 years ago
Views: 313
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For 60n to be a multiple of 825, every prime factor of 825 must exist in 60n. Right now, 60n already has 3 and 5. It is missing 2^2, another 5 and 11. Therefore, n=2^2x5x11=220.
Date Posted:
4 years ago
:)
sorry, wrong ans. was probably tired that day haha. the other tutor’s answer is correct!
Nah it is okay. :)
you’re very kind!
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Answer is shown as above.
Date Posted:
4 years ago
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