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secondary 3 | A Maths
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Kevin Ang
Kevin Ang

secondary 3 chevron_right A Maths chevron_right Singapore

Can I please ask for help? I’m stuck. Thank you!

Date Posted: 4 years ago
Views: 317

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Eric Nicholas K
Eric Nicholas K's answer
5997 answers (Tutor Details)
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To rationalise a denominator in the square root of the form a + ./ b, we introduce what we call the conjugate of a + ./ b, which will be a - ./ b.

a + ./b and a - ./b are conjugate pairs because their product in this case result in a number which is free of square roots, provided that a and b begin without any square roots at all.
Kevin Ang
Kevin Ang
4 years ago
:)