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sorry, (a)(ii) & (b)(ii) incorrect.
corrections ...
(a)(ii) at most 1 married couple
also must include cases where other then the 1 couple, the remaining 2 may also include single members of the other couples.
consider case of committee with 2 couples
ways = 3C2 = 3
then for committee with at most 1 couple
ways = 210 - 3 = 207
(easier to calculate as complement, because too many different possible cases, if calculate directly)
(b)(ii) one couple absent and others sit without restrictions
ways = 10P8/10 = 181440
(not necessary to divide by 2!)
corrections ...
(a)(ii) at most 1 married couple
also must include cases where other then the 1 couple, the remaining 2 may also include single members of the other couples.
consider case of committee with 2 couples
ways = 3C2 = 3
then for committee with at most 1 couple
ways = 210 - 3 = 207
(easier to calculate as complement, because too many different possible cases, if calculate directly)
(b)(ii) one couple absent and others sit without restrictions
ways = 10P8/10 = 181440
(not necessary to divide by 2!)