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Primary 3 | Maths
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Date Posted: 4 years ago
Views: 571
Is this an Olympiad question?
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The answer is (b).
The smallest number of petal that can remain is 2.
The smallest number of petal that can remain is 2.
Thank you!
1) [6, 7, 8, 11]
2) [6, 6, 7, 10]
3) [6, 5, 6, 9]
4) [5, 5, 5, 8]
5) [5, 4, 4, 7]
6) [4, 4, 3, 6]
7) [3, 3, 3, 5]
8) [3, 2, 2, 4]
9) [2, 1, 2, 3]
10) [1, 1, 1, 2]
11) [1, 0, 0, 1]
So you can have 2 petals remaining.
It is impossible to have less than 2 petals remaining, because there is a total of
: 6 + 7 + 8 + 11 = 32 petals.
Each time you pluck one petal each from 3 flowers, you remove a total of 3 petals.
After 10 steps, you remove a total of 10 × 3 = 30 petals.
You can't remove any more, because 32 - 30 = 2 petals remaining.
There can be no next step because 3 is bigger than 2.
2) [6, 6, 7, 10]
3) [6, 5, 6, 9]
4) [5, 5, 5, 8]
5) [5, 4, 4, 7]
6) [4, 4, 3, 6]
7) [3, 3, 3, 5]
8) [3, 2, 2, 4]
9) [2, 1, 2, 3]
10) [1, 1, 1, 2]
11) [1, 0, 0, 1]
So you can have 2 petals remaining.
It is impossible to have less than 2 petals remaining, because there is a total of
: 6 + 7 + 8 + 11 = 32 petals.
Each time you pluck one petal each from 3 flowers, you remove a total of 3 petals.
After 10 steps, you remove a total of 10 × 3 = 30 petals.
You can't remove any more, because 32 - 30 = 2 petals remaining.
There can be no next step because 3 is bigger than 2.
Thank you for ur explanation!
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