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primary 6 | Maths
| Ratio
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Date Posted: 4 years ago
Views: 532
Let a be the number of days in the first scenario and b be the number of day in the second scenario.
Number of green apples sold in the first scenario
=76a + 56
Number of red apples sold in the first scenario
=57a
Number of green apples sold in the second scenario = 48b +284
Number of red apples sold in the second scenario
= 72b
57a = 72 b
19a = 24b
38a = 48b (First equation)
76a + 56 = 48b +284 (Second equation)
Sub 48b= 38a from the first equation into the second equation.
76a + 56= 38a +284
38a = 228
a=6
Number of red apples = 57 x 6 = 342
Cost of red apples = 342 x 0.6 = $205.20
Number of green apples sold in the first scenario
=76a + 56
Number of red apples sold in the first scenario
=57a
Number of green apples sold in the second scenario = 48b +284
Number of red apples sold in the second scenario
= 72b
57a = 72 b
19a = 24b
38a = 48b (First equation)
76a + 56 = 48b +284 (Second equation)
Sub 48b= 38a from the first equation into the second equation.
76a + 56= 38a +284
38a = 228
a=6
Number of red apples = 57 x 6 = 342
Cost of red apples = 342 x 0.6 = $205.20
Thank you, but this looks like algebra which I am afraid to try. Mr AC Lim has helped me with the question already. But thank you.
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Hope this helps
Date Posted:
4 years ago
Thank you for helping as i couldn’t understand algebra so this explanation helps !!
Thank you so much !!
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