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Question
primary 6 | Maths
| Percentage
2 Answers Below
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Date Posted: 4 years ago
Views: 233
Backward calculation.
In the end, both have same number of marbles
Each have = 2660 ÷ 2 = 1330
B transfer 30% to A
B left 70% = 1330
30% = 30÷70 x 1330 = 570 marbles
B Transferred 570 to A
A received 570 become 1330.
A have 1330 - 570 = 760 after transferred 60% of marbles to B.
A left 40% = 760 after transferred 60% to B.
Therefore, A at 1st = 100%
=100÷40 x 760
= 1900 marbles.
B at 1st = 2660 - 1900 = 760
Ans:
A= 1900
B= 760
Hope this helps
In the end, both have same number of marbles
Each have = 2660 ÷ 2 = 1330
B transfer 30% to A
B left 70% = 1330
30% = 30÷70 x 1330 = 570 marbles
B Transferred 570 to A
A received 570 become 1330.
A have 1330 - 570 = 760 after transferred 60% of marbles to B.
A left 40% = 760 after transferred 60% to B.
Therefore, A at 1st = 100%
=100÷40 x 760
= 1900 marbles.
B at 1st = 2660 - 1900 = 760
Ans:
A= 1900
B= 760
Hope this helps
See 2 Answers
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Hope this helps
Date Posted:
4 years ago
done
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A different straight forward method
Date Posted:
4 years ago
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