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secondary 3 | E Maths
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then ones digit is 6-x
value of the number is 10x+(6-x).
product of digits is (1/3) of original number
x(6-x) = (1/3)[10x+(6-x)]
…….
x^2-3x+2=0
(x-1)(x-2)=0
x = 1 or 2
the original number is 15 or 24 (2 possible answers)
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