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Secondary 1 | Maths
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Date Posted: 4 years ago
Views: 436
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For (a):
Just do index notation for both 30 and 126, where you’ll get the HCF by multiplying the numbers obtained by factorization as shown.
For (b):
If you want a perfect cube from any number multiplied by an unknown k, the cubic root of the number must give you a whole number. Since 126=2 x 3^2 x 7, you need to change it such that each 2,3 and 7 becomes cubic numbers(eg. 2 become 2^3, 3 become 3^3 and 7 become 7^3). So to interpret this, 126k=2^3 x 3^3 x 7^3). Divide 126k by 126 to obtain k.
For (c):
If you want 30n to be a multiple of 126, the index notations of each number must have a similar divisible number. In this case, find n by multiplying 30 with numbers similar to the index notation of 126.
For (a):
Just do index notation for both 30 and 126, where you’ll get the HCF by multiplying the numbers obtained by factorization as shown.
For (b):
If you want a perfect cube from any number multiplied by an unknown k, the cubic root of the number must give you a whole number. Since 126=2 x 3^2 x 7, you need to change it such that each 2,3 and 7 becomes cubic numbers(eg. 2 become 2^3, 3 become 3^3 and 7 become 7^3). So to interpret this, 126k=2^3 x 3^3 x 7^3). Divide 126k by 126 to obtain k.
For (c):
If you want 30n to be a multiple of 126, the index notations of each number must have a similar divisible number. In this case, find n by multiplying 30 with numbers similar to the index notation of 126.
Date Posted:
4 years ago
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