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primary 5 | Maths
| Fractions
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Need help in this 2 qns. Thanks in advance
Date Posted: 4 years ago
Views: 580
Qns 8 can explain without using ratio.
8.
method 1
at first
f. bks: 3u
n-f. bks: 1u
total: 4u
at first
f. bks: 3u + 592
n-. bks: 1u
total: 4u + 592
3u + 592 = 5/6 x (4u + 592)
3u + 592 = 20u/6 + 1480/3
1u/3 = 592 - 1480/3 = 296/3
1u = 296
at first, total = 1184
.
method 2
n-f bks no change
3/4 = 5/6
18/24 = 20/24
diff. = 20-18 = 2
2u = 592
1u = 296
at first, total = 4u = 1184
.
.
.
method 1
at first
f. bks: 3u
n-f. bks: 1u
total: 4u
at first
f. bks: 3u + 592
n-. bks: 1u
total: 4u + 592
3u + 592 = 5/6 x (4u + 592)
3u + 592 = 20u/6 + 1480/3
1u/3 = 592 - 1480/3 = 296/3
1u = 296
at first, total = 1184
.
method 2
n-f bks no change
3/4 = 5/6
18/24 = 20/24
diff. = 20-18 = 2
2u = 592
1u = 296
at first, total = 4u = 1184
.
.
.
See 1 Answer
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Have you learnt Ratio? If you have then use this method...hope this helps
Date Posted:
4 years ago
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