Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
Secondary 1 | Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Please help with this question, thank you.
Date Posted: 4 years ago
Views: 557
Let's break the HCF and LCM down into their prime factors.
HCF
= 6
= 2 x 3
LCM
= 336
= 2 x 2 x 2 x 2 x 3 x 7
= 2^4 x 3 x 7
-----------------------------------------------------
For two numbers to meet BOTH the HCF and LCM conditions, they must meet the following.
1. One of the numbers MUST have exactly one "2" as a factor, while the other number MUST have exactly four "2"s as a factor. Any breach of this condition results in either the HCF or LCM condition not being met.
2. BOTH numbers MUST have exactly one "3" each as a factor, since both the HCF and LCM contain only one "3". Any breach of this condition results in either the HCF or LCM condition not being met.
3. One of the numbers MUST have exactly one "7" as a factor, while the other number CANNOT have any "7" in it. Any breach of this condition results in either the HCF or LCM condition not being met.
-----------------------------------------------------
We can rewrite 48 as 2^4 x 3.
-----------------------------------------------------
48 contains four "2"s and one "3". Based on the three requirements above, the other number MUST have one "2", one "3" and one "7".
Thus, the other number is 2 x 3 x 7 = 42.
HCF
= 6
= 2 x 3
LCM
= 336
= 2 x 2 x 2 x 2 x 3 x 7
= 2^4 x 3 x 7
-----------------------------------------------------
For two numbers to meet BOTH the HCF and LCM conditions, they must meet the following.
1. One of the numbers MUST have exactly one "2" as a factor, while the other number MUST have exactly four "2"s as a factor. Any breach of this condition results in either the HCF or LCM condition not being met.
2. BOTH numbers MUST have exactly one "3" each as a factor, since both the HCF and LCM contain only one "3". Any breach of this condition results in either the HCF or LCM condition not being met.
3. One of the numbers MUST have exactly one "7" as a factor, while the other number CANNOT have any "7" in it. Any breach of this condition results in either the HCF or LCM condition not being met.
-----------------------------------------------------
We can rewrite 48 as 2^4 x 3.
-----------------------------------------------------
48 contains four "2"s and one "3". Based on the three requirements above, the other number MUST have one "2", one "3" and one "7".
Thus, the other number is 2 x 3 x 7 = 42.
See 1 Answer
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Check the answer and let me know if you have trouble understanding it.
Date Posted:
4 years ago
360 Tutoring Program