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For Q11, when you threw away the same number of fruits, the difference between the 2 fruits remains the same.
A → Apples
O → Oranges
At first,
A : O = 2 : 3
Difference between apples and oranges at first was:
3-2 = 1 unit
In the end,
A : (A+O) = 2 : 7
where (A+O) is the total fruits (apples and oranges combined).
To find the units for oranges in the end,
7-2 = 5 units
Hence, in the end,
A : O = 2 : 5
Difference between apples and oranges in the end became:
5-2 = 3 units
Therefore, we need to multiply the ratio at first by 3.
A : O = 2 : 3 = 6 : 9
By doing so, the difference between A and O at first and in the end will both be the same (3 units).
Now, we must find how many units are 48 rotten fruits.
A → 6-2 = 4, or
O → 9-5 = 4
By comparing the apples (or oranges) at first and in the end, it’s clear that:
4 units → 48
1 unit → 12
Oranges (at first):
9 units → 12 x 9 = 108
A → Apples
O → Oranges
At first,
A : O = 2 : 3
Difference between apples and oranges at first was:
3-2 = 1 unit
In the end,
A : (A+O) = 2 : 7
where (A+O) is the total fruits (apples and oranges combined).
To find the units for oranges in the end,
7-2 = 5 units
Hence, in the end,
A : O = 2 : 5
Difference between apples and oranges in the end became:
5-2 = 3 units
Therefore, we need to multiply the ratio at first by 3.
A : O = 2 : 3 = 6 : 9
By doing so, the difference between A and O at first and in the end will both be the same (3 units).
Now, we must find how many units are 48 rotten fruits.
A → 6-2 = 4, or
O → 9-5 = 4
By comparing the apples (or oranges) at first and in the end, it’s clear that:
4 units → 48
1 unit → 12
Oranges (at first):
9 units → 12 x 9 = 108
For the last step, just remember that we need to use the new ratio (6 : 9) instead of the old one (2 : 3).